Systems of equations practice

Systems of Three Equations worksheets

Solve three-variable linear systems by true elimination or substitution, including one solution, infinitely many solutions, and no solution.

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Solve each system with the selected method. Give an exact triple, complete parameterization, or explicit contradiction.

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Show the method, not only the classification

Elimination keys retain legal whole-row operations. Substitution keys isolate a variable, use that expression in both remaining equations, and continue the substitution.

Learning objective

What this activity builds

Use exact row operations or recursive substitution to classify and solve systems in x, y, and z.

Worked example

What proves that a system has no solution?

A legal derivation that reaches 0 = c for a nonzero exact number c.

The contradiction shows the original equations cannot all hold at once.

Teaching notes

Make the practice count

  • Keep each whole-row operation visible.
  • For substitution, put the first isolated expression into both remaining equations.
  • Check a unique ordered triple in all three originals.

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Math SheetNameScoreTeacherDateSystems of Three EquationsSolve each three-equation system with the selected method. Give an exact ordered triple, a complete parameterization, or a clear contradiction.1. Solve by elimination.x + y + z = 2x + 2y + 2z = 5x + 3y = 22. Solve by elimination.x + 2y + 2z = -2x + 4y + z = -1x + 6y = 1Method: elimination. Keep all values exact.math-sheet.comPage 1 of 3
Math SheetNameScoreTeacherDateSystems of Three EquationsSolve each three-equation system with the selected method. Give an exact ordered triple, a complete parameterization, or a clear contradiction.3. Solve by elimination.x + y + z = 22x + 2y + 2z = 4-x - y - z = -24. Solve by elimination.x + z = 3x + 2y = 4x + y + 3z = 7Method: elimination. Keep all values exact.math-sheet.comPage 2 of 3
Math SheetNameScoreTeacherDateSystems of Three EquationsSolve each three-equation system with the selected method. Give an exact ordered triple, a complete parameterization, or a clear contradiction.5. Solve by elimination.x - 2y + z = 2x - y + 3z = 5x - 5y - 5z = -66. Solve by elimination.x + 2y + 2z = -2x + 4y + z = -1x + 6y = 0Method: elimination. Keep all values exact.math-sheet.comPage 3 of 3